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- Mutually Exclusive Events

This question was previously asked in

SSC CGL Tier-II ( JSO ) 2017 Official Paper ( Held On : 22 Feb 2018 )

- 0.1
- 0.3
- 0.6
- 0.4

Option 2 : 0.3

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314011

10 Questions
10 Marks
7 Mins

**Given**

P(A) = 2P(B) = 6P(C)

**Concept**

When event are mutually exclusive and exhaustive

P(A) + P(B) + P(C) = 1

**Calculation**

Let P(A) be k

⇒ P(B) = k/2

⇒ P(C) = k/6

So according to the concept

⇒ k + k/2 + k/6 = 1

⇒ 10k/6 = 1

⇒ k = 3/5

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